0.25x^2-3x+2.8125=0

Solution for 0.25x^2-3x+2.8125=0 equation:

0.25x^2-3x+2.8125=0

a = 0.25; b = -3; c = +2.8125;
Δ = b2-4ac
Δ = -32-4·0.25·2.8125
Δ = 6.1875
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{6.1875}}{2*0.25}=\frac{3-\sqrt{6.1875}}{0.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{6.1875}}{2*0.25}=\frac{3+\sqrt{6.1875}}{0.5}
$